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18x^2+6x-684=0
a = 18; b = 6; c = -684;
Δ = b2-4ac
Δ = 62-4·18·(-684)
Δ = 49284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49284}=222$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-222}{2*18}=\frac{-228}{36} =-6+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+222}{2*18}=\frac{216}{36} =6 $
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